STOIKIOMETRI
1. Understanding Stokiometri
Stoichiometry is the basic chemical
calculation that states quantitative relation of chemical formulas and chemical
equations. Here
are the materials you need to know to understand, from the concept of moles and
molar masses, empirical formulas and molecular formulas, basic stoichiometry of
solutions and ideal gases, and the writing and equalization of reactions, with
examples of problems and discussions.
2.
The
concept of Moles and Molar Mass
In SI
systems, one mole is defined as the sum of the material composed of entities
(atoms, molecules, or other particles) a sum of the atoms in 12 grams of
carbon-12. The
value of the number of atoms is 6.022 × 1023 called the Avogadro number, NA.
The molar mass is defined as the mass of 1 mol entity (atom, ion, molecule, unit of formula) of matter. The unit of the molar mass is grams / mol.
The molar mass is defined as the mass of 1 mol entity (atom, ion, molecule, unit of formula) of matter. The unit of the molar mass is grams / mol.
Stoichiometric Material: Mass relation, number of moles,
and number of atoms of the element
(Source:
Chang, Raymond, 2010. Chemistry (10th edition) New York: McGraw Hill)
3.
Empirical
Formulas and Molecular Formulas
The
empirical formula is the simplest integer ratio of the number of moles of each
element in a compound. The
molecular formula represents the true number of moles of each element in 1 mole
of the compound. The
molecular formula may be identical to the empirical formula or an integer
multiple of the empirical formula. For
example, phosphoric acid (H3PO4) has a molecular formula and an identical
empirical formula. Glucose
has a molecular formula C6H12O6 which is a folding of 6 times its empirical
formula, CH2O.
Molecular Formula ≡ (Empirical Formula) n
Molecular formula = n × empirical formula, n = 1, 2,
3, ...
4.
Basic
Stoichiometric Solution
The term
"concentration" of the solution expresses the amount of solute dissolved
in a certain amount of solvent or a certain amount of solution. The concentration
of the solution can be expressed in molarity. Molarity
(M) is defined as the number of moles of solute per liter of solution.
5.
Basic
Ideal Gas Stoichiometry
The molar
volume, Vm, is defined as the volume of 1 mol entity (atom, ion, molecule, unit
of formula) of matter. The
unit of the molar volume (Vm) is L / mol.
Avogadro's
law states that at certain pressures and temperatures and fixed, the volume of
gas is directly proportional to the amount of gas.
In the STP state (P = 1 atm, T = 273 K), ideal gas Vm =
22.414 L / mol
In the case of RTP / ATP (P = 1 atm, T = 298 K), ideal
gas Vm = 24 L / mol
In certain circumstances, an ideal gas law applies:
Where R is the gas constant, R = 0.08206 L ∙ atm / mol ∙
K = 8.314 J / mol ∙ K
6.
Writing
and Equalizing Chemical Reaction Equations
The
chemical reaction equation is a statement written with a molecular formula that
provides information on the identity and quantity of substances involved in a
chemical or physical change. All
reacting substances, called reactants, are placed to the left of the arrow,
whose direction of the arrow to the right refers to the product, ie all the
substances produced from the reaction.
In the
equation of the reaction, the reaction coefficient is known, which is the
number on the left of the molecular formula for multiplying all the atoms in
the molecular formula. The
comparison of the reaction coefficients can be interpreted as the mole ratio of
the substances in the reaction. In
each of the reactants and products, it is written in the form of the substance
(s (solid), l (liquid), g (gas), or aq (solution with water solvent)) in
brackets to the right of each molecular formula.
Example of equivalent chemical reaction equation:
Example of steps equalizing the reaction equation:
1.
2.
3.
4.
7.
Stoichiometry
Reaction
In
chemical reactions, the amount of reacting reactants is sometimes incompatible
with the stoichiometric amount of the reaction (not in accordance with the
coefficient ratio of the equivalent equation). Therefore,
there will be reactants that have reacted first compared to other reactants. The
reactants that remain after reacting are called excess reagents. The
out-of-date reactant is called a limiting reagent. After
the barrier reagents are exhausted, no more reaction products are formed. Thus,
the number of limiting reagents determines the amount of product produced.
Sample Stoichiometric
Problem
Consider the following reactions:
Answer :
a.
Apply
the chemical reaction that occurs if the equation of the reaction is not equal.
In
the above equation the equation is equal so it does not need to be equalized.
b. Declare the number of moles of known
substance, ie aluminum
d. Determine the volume of H2 gas produced
V = n x Vm
= 0.3 mol x 22.4 L mol ~ 1
= 6.72 L.
Stoichiometry – References
-
Brown, Theodore L. et al. 2015. Chemistry: The Central Science (13th
edition). New Jersey: Pearson Education, Inc.
- Chang, Raymond. 2010. Chemistry (10th edition). New York: McGraw Hill
- Earl, Bryan & Wilford, Doug. 2014. Cambridge IGCSE® Chemistry (3rd edition). London: Hodder Education.
- Gilbert, Thomas N. et al. 2012. Chemistry: The Science in Context (3rd edition). New York: W. W. Norton & Company, Inc.
- Jespersen, Neil D., Brady, James E., & Hyslop, Allison. Chemistry: The Molecular Nature of Matter (6th edition). New Jersey: John Wiley & Sons, Inc.
- Petrucci, Ralph H. et al. 2011. General Chemistry: Principles and Modern Applications (10th edition). Toronto: Pearson Canada Inc.
- Purba, Michael. 2006. Kimia 1A untuk SMA Kelas X. Jakarta: Erlangga.
- Silberberg, Martin S. 2009. Chemistry: The Molecular Nature of Matter and Change (5th edition). New York: McGraw Hill
- Stacy, Angelica M. 2015. Living by Chemistry (2nd edition). New York: W.H. Freeman and Company
- Tro, Nivaldo J. 2011. Introductory Chemistry (4th edition). Illinois: Pearson Prentice Hall
- Chang, Raymond. 2010. Chemistry (10th edition). New York: McGraw Hill
- Earl, Bryan & Wilford, Doug. 2014. Cambridge IGCSE® Chemistry (3rd edition). London: Hodder Education.
- Gilbert, Thomas N. et al. 2012. Chemistry: The Science in Context (3rd edition). New York: W. W. Norton & Company, Inc.
- Jespersen, Neil D., Brady, James E., & Hyslop, Allison. Chemistry: The Molecular Nature of Matter (6th edition). New Jersey: John Wiley & Sons, Inc.
- Petrucci, Ralph H. et al. 2011. General Chemistry: Principles and Modern Applications (10th edition). Toronto: Pearson Canada Inc.
- Purba, Michael. 2006. Kimia 1A untuk SMA Kelas X. Jakarta: Erlangga.
- Silberberg, Martin S. 2009. Chemistry: The Molecular Nature of Matter and Change (5th edition). New York: McGraw Hill
- Stacy, Angelica M. 2015. Living by Chemistry (2nd edition). New York: W.H. Freeman and Company
- Tro, Nivaldo J. 2011. Introductory Chemistry (4th edition). Illinois: Pearson Prentice Hall
Would you give me another example of Sample Stoichiometric Problem and an easy way to solve it?
BalasHapus[L = 6.02 x 1023] Calculate the particle count of:
HapusA) 0.6 mol of SO2 gas
B) 28 grams of iron (Fe)
C) 6.72 liters of NO2 gas in STP state
Ar S = 32, N = 14, O = 16, Fe = 56
DISCUSSION:
A) 0.6 mol of SO2 gas
→ 0.6 x 6.02 x 1023 = 3.612 x 1023 SO2 molecule
B) 28 grams Iron (Fe)
→ Mol Fe = Fe Mass: mm = 28 grams: 56 = 0,5 mol
Number of particles Fe = 0.5 x 6.02 x 1023 = 3.01 x 102
C) 6.72 liters of NO2 gas
→ Mol NO2 = Volume NO2: 22.4 = 0.3 mol
Number of particles NO2 = 0.3 x 6.02 x 1023 = 1,806 x 1023
Give a question and its solution about the ideal gas, molarity and molar volume.
BalasHapusExample of Gas Molar Volumes
Hapus1. Calculate the volume of 4 grams of SO3 in STP state. If it is known Ar S = 32; O = 16.
Answer:
Mr. SO3 = 80 (if still confused Mr. count please visit relative molecular mass)
SO3 molar mass = 80 gram / mol
So, 4 grams SO3 = 4 gram / 80 ram / mol
The volume at STP = 0.05 mol x 22.4 liter / mol
= 1.12 liters
Komentar ini telah dihapus oleh pengarang.
BalasHapusKomentar ini telah dihapus oleh pengarang.
HapusHaii ulekk... Can you explain with your opinion about stoichiometri ???
BalasHapusIn my opinion stoichiometry is a basic calculation in chemistry
Hapushow to find empirical formula? can you explain?
BalasHapus
HapusThe Empirical Formula is a formula that expresses the smallest comparisons of atoms composing a compound.
Example An organic compound is made up of 40% carbon, 6.6% hydrogen, and the remaining oxygen. (Ar C = 12, H = 1, O = 16). If mr = 90. Find the empirical formula and the molecular formula of the compound!
Answer:
C = 40%, H = 6.6%, O = 100 - (40 + 6.6) = 53.4%
Mol C: mol H: mol O = 40/12: 6,6 / 1: 53,4 / 16
= 3.3: 6,6: 3,3
= 1: 2: 1
So, the empirical formula is CH2O
Why sthoiciometric including difficult material in chemistry?
BalasHapusBecause stoichiometry is the basic chemical calculation, if we do not understand the basic then we are difficult to deepen chemistry
HapusWhat is the function and usefulness of moles in stoichiometry?
BalasHapusMol is very functional because to find the volume and molarity of a solution must have a mole. Mol is the molecular weight divided by the relative molecular mass
HapusWhat are the relationship between volume and mass?
BalasHapusWe can say that the mass of gas (m) is proportional to the alias proportional to the volume of gas (V) known as the ideal gas law
HapusHow to write the correct chemical equation?
BalasHapusWriting a Reaction Equation
HapusWriting a reaction equation can be done in three steps as follows:
A. Write down the equation of words consisting of the name and state of the reactant substances (substances) and the name and state of the reaction substance (substance).
B. Write equations of formulas comprising the chemical formula of the reactant substances and substances (substances) of the reaction, together with a description of the state.
C. Equalize, ie give the appropriate coefficient so that the number of atoms of each element is the same on both sides.